What is the simplified form of i ^32?
a. -i
b. 1
c. i
d. -1

divide exponent by 4

since the remainder is zero, the equation can be rewritten as i^0 and any number to the 0 power is 1

1

Step-by-step explanation:

The pattern of imaginary numbers taken to exponents goes as thus:

i^1= i

i^2= -1

i^3= -i

i^4= 1

To solve this problem, divide the exponent by 4:

32/4= 8

Now rewrite i^32 as (i^4)^8  

(When exponents are raised by an exponent you multiply them together)

i^4=1, this is your answer

17 1/3

step-by-step explanation: