Apublisher reports that 35% of their readers own a particular make of car. a marketing executive wants to test the claim that the percentage is actually less than the reported percentage. a random sample of 140 found that 25% of the readers owned a particular make of car. is there sufficient evidence at the 0.02 level to support the executive's claim?

There is sufficient evidence to support the executive's claim.

Step-by-step explanation:

We will do a two-tailed test of the proportion.

Null hypothesis H0: p=0.35

Alternative hypothesis: p≠0.35

The significance level is 0.02.

Calculation of the standard deviation

Calculation of the z-score

Since we have a two-tailed test, the P-value is the probability that the z-score is less than -2.5 or greater than 2.5.

Calculation of the P-value

Since the P-value (0.012) is smaller than the significance level (0.02), we can reject the null hypothesis.

There is sufficient evidence to support the executive's claim.

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3