Here are two closed containers and four balls just fit into each container. each ball has a diameter of 60mm. which container has the smaller surface area? you must show your working. mathswatch

"A is smaller"

Step-by-step explanation:

The full question is attached.

Surface area of cylinder:

The formula is  

where r is the radius and h is the height

Here, radius would be 30 since balls have diameter 60 and radius is half of that.

Also height is the diameter of 4 balls line-by-line, so height is 60*4 = 240

Now, plugging into the formula, we get:

Surface Area of rectangular prism:

The surface area of rectangular prism is the area of all the rectangular surfaces (6 of them).

Area of top and bottom = (60+60)*(60+60) * 2 = 120*120 * 2 = 28,800

Area of 2 sides = 2 * (60*120) = 14,400

Area of front and back = 2 * (60*120) = 14,400

Total Surface Area = 28,800 + 14,400 + 14,400 = 57,600

Thus, cylinder has smaller surface area.

"A is smaller"

2827.433388 x 2 = 5654.866776

188.4955592 x 240 = 45238.93421

50893.80099

60 x 120 x 4 = 28800

120 x 120 x 2  = 28800

28800 + 28800 = 57600

'A is smaller'

I have put that into Mathswatch and this is the correct answer

you need a common difference between consecutive terms to be constant, like 1,2,3,4 or 2,4,6,8, or 1,3,6,9

i think c. but don't trust it.

step-by-step explanation: