Which ordered pair is a solution of the equation?
3x−y=13 3x-y=13
3x−y=13
3, x, minus, y, equals, 13
choose 1
choose 1
(choice a)
a
only
(6,5)(6,5)
(6,5)
left parenthesis, 6, comma, 5, right parenthesis
(choice b)
b
only
(3,−4)(3,-4)
(3,−4)
left parenthesis, 3, comma, minus, 4, right parenthesis
(choice c)
c
both
(6,5)(6,5)
(6,5)
left parenthesis, 6, comma, 5, right parenthesis
and
(3,−4)(3,-4)
(3,−4)
left parenthesis, 3, comma, minus, 4, right parenthesis
(choice d)
d
neither

C- both (6,5) and (3,-4)

Step-by-step explanation:

3x-y=13

3(6)-5=13

18-5=13

13=13

3x-y=13

3(3)-(-4)=13

9+4=13

13=13

answer is c

step-by-step explanation:

proportions are fractions that equal to each other. so if two fractions are the same, they are proportional.

let's check the answers to see if they are proportional.

question a is not proportional because you can't turn 1.5/3 to 3/9. if you try to multiply 1.5/3 by 2 or 3, you wont get 3/9. it's impossible to make the fractions the same.

question b is not proportional because you can't turn 22/33 to 4/6. 33 can't go into 6.

question c is proportional because when you multiply 2 and 3 by 71, you would get 142/213, and those fractions equal to each other

question d is proportional because when you divide 14 and 7 by 2, you would end up with 7/3.5, and those fractions equal to each other.