Given that f(x)=x^2-4x-3 and g(x)= x+3/4, solve for f(g(x)) when x=9.

f(g(x)) when x=9 would be -129/4

Step-by-step explanation:

First, you split the parts into two.

f(g(x)) and g(x). *Think of g(x) as the y of f, f(y).

Now you solve for g(x), where you would plug in 9, for the x.

(9)+3/4 which equals, 39/4.

Now you have solved for g(x), and you have to plug it into the "y" of f.

f(y) = y^2-4y-3

f(39/4) = (39/4)^2-4(39/4)-3

f(39/4) = -129/4

Your solution should be -129/4.

1,918

step-by-step explanation:

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.