Abigail is 8years older than cynthia. twenty years ago abigail was three times as old as cynthia. how old are each now?

Abigail age=32 and Cynthia age=24

Step-by-step explanation:

Abigail is 8years older than Cynthia. Twenty years ago Abigail was three times as old as Cynthia

LEts A be the age of Abigail

and C be the age of Cynthia

Abigail is 8years older than Cynthia

A = C+8

Twenty years ago Abigail was three times as old as Cynthia

A-20= 3(C-20)

WE use both equation and solve for A  and C

Replace A with C+8

C+8-20= 3(C-20)

C-12 = 3C - 60

Subtract 3C from both sides

-2C - 12= -60

Add 12 on both sides

-2C= -48

divide both sides by -2

C= 24

LEts find out A

A= C+8

A= 24+8 = 32

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation:

answer: $201

step-by-step explanation: to get the answer, you first get 3 nieces that he sold and multiply it by 67 and get $201, so he earned $201 selling his nieces.