Which equatjon has an extraneous solution?
a. x - 2 = square x
b. square 10x - 16 = 2
c. square x + 4 + 1 = 1
d. square x + 1 =2

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..

dont trust me im no expert these losers made me fail a test bro this sucks

step-by-step explanation: