Someone find the answer, ill give brainliest.
find the perimeter and area of the figure shown below. use 3.14 for π. round your answer to the nearest hundredth.
perimeter =
area =

SQUARE IN THE MIDDLE

This is the easiest part: a square with side length s has area s^2, so the area of the square in the middle is

TRIANGLE ON THE LEFT

The base of this triangle is one side of the square, so it is 12 inches long. The height is given, and it is 8 inches long. The area of a triangle is half the product of width and height, and so we have

SEMICIRCLE ON THE RIGHT

The diameter of the semicircle is one side of the square, so it is 12 inches long. The radius is half the diameter, so it's 6 inches long. The area of a circle is , so the area of a semicircle will be half this quantity:

The total area is the sum of these areas:

As for the perimeter, we have:

Since the circumference of a circle is , the semicircumference will be

So, the perimeter is

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc