Abaker bakes a batch of muffins and splits the batch evenly onto six different trays. she then adds five croissants to each tray. if each tray now contains at least twenty baked goods, what is the least possible number of muffins in the baker's original batch?

90

Step-by-step explanation:

Using inequalities we can understand this problem.

First call X the number of products in the original batch

Then X/6 is the number of muffins in each tray before putting the croissants

Finally, X/6+5 are the products in each tray counting the croissants, and this quantity at least should be 20, it means:

Isolating X:

The least possible number of muffins in the baker's original batch is 90.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

honesty mood

step-by-step explanation: