The hundreds digit of the five-digit number 73_95 is missing. if the hundreds digit is to be randomly selected from the ten different digits from 0 to 9, what is the probability that the resulting five-digit number will be a multiple of 3?
a. 0
b. 110
c. 310
d. 25
e. 12

D

Step-by-step explanation:

7+3+9+5=24

which is divisible by 3

so reqd. digit should be multiple of 3

multiples of 3 are 0,3,6,9

so probability=4/10=2/5

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

not me

step-by-step explanation:

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