the area of a certain rectangle is 288 yd2. the perimeter is 68 yd. what are the dimensions of the rectangle?
a) 24 yd by 10 yd
b) 18 yd by 16 yd
c) 22 yd by 12 yd
d) 36 yd by 8 yd
show work-thx

The rectangle is 16*18

Step-by-step explanation:

The area of a rectangle is length * width and the perimeter is 2 times length * width

A = l*w

P = 2(l+w)

Replacing A and P

288 = l*w

68 = 2(l+w) => 34 = l+w => 34 - w = l

replacing l in the area

288 = (34 - w) w

w^2 - 34w + 288 = 0

(w - 16)(w - 18)

w = 16

w = 18

replacing in 34 - w = l

you get that when w = 16, l = 18 and when w = 18, l = 16

europa2433

europa2433

step-by-step explanation:

he has now walked a total of what?

if i know what this is maybe i can

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