Write the equation of a line parallel and perpendicular to the given line and passing through (1, -1), y=2/5x-3

Parallel: y = (2/5)x - 7/5

Perpendicular: y = (-5/2)x + 3/2

Step-by-step explanation:

Parallels lines have the same slope,

And it also needs to pass through (1, -1)

for an equation as y = mx + b, the only information missing is the y-intercept, it can be found replacing everything else.

-1 = (2/5)(1) + b

-1 - 2/5 = b

-7/5 = b

The equation for the line parallel is y = (2/5)x - 7/5

Perpendiculars when you multiply its slopes the result is -1 , assuming m = the slope of the perpendicular line

(2/5) * m = -1

m = -5/2

Now you have to replace the point and the slope to get the y-intercept as the previous line:

y = mx + b

-1 = (-5/2)(1) + b

-1 + 5/2 = b

3/2 = b

y = (-5/2)x + 3/2

-14 is the answer

hope this : ))