Me!
question 1 (essay worth 10 points)
(01.02 mc)
part a: if (7^2)x = 1, what is the value of x? explain your answer. (5 points)
part b: if (7^0)x = 1, what are the possible values of x? explain your answer. (5 points)

Step-by-step explanation:

A.

(7^2)^x = 1

(49)^x = 1

thus x = 0

B.

(7^0)^x=1

(1)^x = 1

x can be any real number.

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3