Suppose an experiment has 3 stages: a, b, and c. if stage a has 6 outcomes, stage b has 4 outcomes, and stage c has 3 outcomes. how many outcomes does the entire experiment have?

72

Step-by-step explanation:

Stage A has 6 outcomes, then B has 4 and C has 3

Take for example only 1 outcome of A, it will have 4 outcomes of B and each outcome of B will have 3 outcomes.

Then a single outcome of A has a total of 12 outcomes (4*3)

Writing it in a way A, B, C:

1,1,1

1,1,2

1,1,3

1,2,1

1,2,2

1,2,3

1,3,1

1,3,2

1,3,3

1,4,1

1,4,2

1,4,3

This is only taking in consideration 1 outcome of A, A has a total of 6 outcomes.

The total of outcomes in the experiment = 6*12=72

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

-9

step-by-step explanation: