The monthly demand for a product is normally distributed with mean = 700 and standard deviation = 200.
1. what is probability demand will exceed 900 units in a month?
2. what is probability demand will be less than 392 units in a month?

Given :The monthly demand for a product is normally distributed with mean = 700 and standard deviation = 200.

To Find :

1. What is probability demand will exceed 900 units in a month?

2. What is probability demand will be less than 392 units in a month?

Solution:

We are supposed to find probability demand will exceed 900 units in a month.

Formula :

We are supposed to find P(Z>900)

Substitute x = 900

Refer the z table.

P(Z<900)=0.8413

P(Z>900)=1-P{(Z<900)=1-0.8413=0.1587

So, the probability that demand will exceed 900 units in a month is 0.1587.

Now we are supposed to find probability demand will be less than 392 units in a month

We are supposed to find P(Z<392)

Substitute x = 392

refer the z table

P(Z<900)=0.0618

So, probability that demand will be less than 392 units in a month is 0.0618.

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step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

ensure that you have copied down this problem correctly.   .