Let d = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36} determine which of the following statements are true and which are false. a) vxe d, if x is odd then x> 0 [select] b) vx e d, if x is less than 0 then x is even [select] c) vxe d, if x is even then xs0 [select] d) vx e d, if the ones digit of x is 2, then the tens digit is 3 or 4 e) vx e d, if the ones digit of x is 6, then the tens digit is 1 or 2 [select]

if x is odd then x> 0 is true statement.

if x is odd then x> 0 is true statement.

if x is even then x≤0 is false statement.

If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

Step-by-step explanation:

Consider the provided information.

D = {-48, -14, -8, 0, 1, 3, 16, 23, 26, 32, 36}

Part (A) if x is odd then x> 0

Here only even numbers are less than 0 that means the statement is true.

if x is odd then x> 0 is true statement.

Part (B) if x is less than 0 then x is even.

Here only even numbers are less than 0 that means the statement is true.

if x is odd then x> 0 is true statement.

Part (C) if x is even then x≤0

Here we can see that 16, 26, 32, 36 are even number and also greater than 0. Thus the statement is false.

if x is even then x≤0 is false statement.

Part (D) If the ones digit of x is 2, then the tens digit is 3 or 4.

There is only one number whose ones digit is 2. i.e. 32 also the tens digit of the number 32 is 3. Which makes the above statement true.

If the ones digit of x is 2, then the tens digit is 3 or 4 is true statement.

Part (E) if the ones digit of x is 6, then the tens digit is 1 or 2.

Numbers having ones digit 6 are: 16, 26 and 36

Here, the tens digits are 1, 2 and 3 which is contradict to our statement. Hence the provided statement is false.

if the ones digit of x is 6, then the tens digit is 1 or 2 is false statement.

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°