An item normally $15.99 is listed as being on sale for 30% off its original price, what must you pay?
a discount store promises that all the items it sells are 40% of their normal asking retail price. if one buys shoes that normally retail for $60.99 what is the price you would expect to pay?
describe how you would answer each question
then rewrite the percent off problem as a percent of problem.

You must pay $11.19 for an item whose original price is $15.99 and is on sale for 30% off its original price.

You must pay $24.40 for an item whose original price is $60.99 and is on sale for 40% of their normal retail price.

Step-by-step explanation:

For the first problem, it states that the item is on sale for 30% off its original price. If the original price is 100%, this means that you will only have to pay 100%-30%=70% of the original price.

There are different ways in which you can calculate a percentage, being the easiest one to turn the 70% into a decimal number and then multiplying it by the original price. In order to turn a percentage into a decimal number, we must divide it into 100% so we get:

so, 70% of $15.99 is:

$15.99*0.7=$11.19

So you must pay $11.19 for an item whose original price is $15.99 and is on sale for 30% off its original price.

The second problem is solved similarly, with the difference that for the second problem, they tell you that the price is directly 40% of its normal retail price, this is we need to calculate 40% of $60.99.

First, we turn the 40% into a decimal number:

and next we calculate the percentage:

$60.99*0.4=$24.40

so

You must pay $24.40 for an item whose original price is $60.99 and is on sale for 40% of their normal retail price.

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.