The number of bacteria in a refrigerated food product is given by n(t) = 24t^2 - 91 t + 65, for 3 < t < 33. the variable t is the temperature of thefood. when the food is removed from the refrigerator, the temperature is given byt(t) = 3 t + 1.6 , where t is the time in hours. find the composite function n(t(t)):

The answer to your question is

Step-by-step explanation:

               N(T)  = 24T² - 91 T + 65         and T(t) = 3t + 1.6

         N(T(t)) = 24(3t + 1.6)² - 91(3t - 1.6) + 65

         N(T(t)) = 24 (9t² + 9.6t + 2.56) - 273t - 145.6t + 65

        N(T(t)) = 216t² + 230.4t + 61.44 - 273t - 145.6 + 65

        N(T(t)) = 216t² - 42.6t - 9.16

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: