The heights of adult men in america are normally distributed, with a mean of 69.3 inches and a standard deviation of 2.68 inches. the heights of adult women in america are also normally distributed, but with a mean of 64.8 inches and a standard deviation of 2.52 inches. a) if a man is 6 feet 3 inches tall, what is his z-score (to two decimal places)? z = ) what percentage of men are shorter than 6 feet 3 inches? round to nearest tenth of a %c) if a woman is 5 feet 11 inches tall, what is her z-score (to two decimal places)? z =) who is relatively taller: a 6'3" american man or a 5'11" american woman? defend your choice in a meaningful sentence.

a) z-score for men is 2.13. b) percentage of men shorter than 6 feet 3 inches is 98%. c) z-score for women is 2.46. d) The American woman is relatively taller.

Step-by-step explanation:

The z-score is calculate by the difference between the value and the mean divided by the standard deviation.  For men, z-score will be 2.13 and for women it will be 2.46. If you reference to the distribution graph, a z-score of about 2 is approximately 98% of cumulative percentage. This means that 98% of men is shorter than 6 feet 3 inches tall. The American woman of 5'11" is relatively taller than a men of 6'3" because of its z-score. Since it is closer to 3, the percentage of women shorter than 5'11" will be over 98% and lower than 99%, which is already taller than the value found for men of 6'3".  

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph