Ok. now we move onto problems where this technique is used, but only towards the end. we also need to
review how to solve problems where the variable shows up more than once. since this is review. we will jump
right into the most complex scenario.
exercise #3: consider the equation 5(x-3)+2x = 4(x+3).
(a) by using the distributive property, write (b) solve the equation for x. check to make sure
equivalent expressions for both sides of the
the original equation has a true value for the x
equation. show the work below.
you find.

i wish i could , i have not learn that

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.