Mathematics, 19.09.2019 17:30 Mintfu8122
Which shows a recursive and an explicit formula for a sequence whose initial term is 14 and whose common difference is β4? a. a(1) = 14; a(n) = (n β 1) β4; a(n) = 14 + (n β 1)(β4) b. a(1) = 14; a(n) = (n + 1) β4; a(n) = 14 + (n β 1)(β4) c. a(1) = 14; a(n) = (n β 1) β 14; a(n) = 14 + (n β 1)(β14) d. a(1) = 14; a(n) = (n + 1) β 14; a(n) = 14 + (n + 1)(14)
Answers: 1
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Which shows a recursive and an explicit formula for a sequence whose initial term is 14 and whose co...
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