At a local cafeteria 10 selections of vegetables are available how many 3 vegetable trays may be made

120

Step-by-step explanation:

This is a combination problem in which order does not matter.

You can choose from 10 vegetables for the first choice.

Then you can choose from 9 vegetables for the second choice.

Finally, you can choose from 8 vegetables for the third choice.

That means the total number of choices is 10 * 9 * 8 if the order mattered.

Since choosing the same three vegetables in any order makes the same choice, you need to divide by the number of ways you can arrange 3 vegetables in a plate.

The number of ways you can arrange 3 vegetables in a plate is 3 * 2 * 1.

The number of combinations is (10 * 9 * 8)/(3 * 2 * 1) = 720/6 = 120

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation: