Going into the final exam, which will count as two tests, brooke has test scores of 79 comma 82 comma 70 comma 63 comma and 94. what score does brooke need on the final in order to have an average score of 80?

Brooke needs 172 on the final exam.

Step-by-step explanation:

Brooke has test scores of 79 comma 82 comma 70 comma 63 comma and 94.  

Total test = 5

Total score = 79+82+70+63+94 = 388

It is given that final exam will count as two tests.

Let Brooke needs x on the final exam.

Total number of tests after final exam = 7

Formula for Average:

Average scare is 80.

Multiply both sides by 7.

Subtract 388 from both sides.

Therefore, Brooke needs 172 on the final exam.

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm