Aconsumer organization inspecting new cars found that many had appearance defects (dents, scratches, paint chips no car had more than three defects. here is the probability distribution for the number of appearance defects in a new car. x = number of defects 0 1 2 3 p(x) 0.58 0.24 0.13 0.05 find the expected number of appearance defects in a new car. enter a number in decimal form. do not round.

0.65

Step-by-step explanation:

When we have a finite number of events  

with its corresponding probabilities

with  

then the expected value of the distribution is given by

In our case, we have

with probabilities

So, the expected value is

E = 0*0.58+1*0.24+2*0.13+3*0.05 = 0.65

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.