You are a researcher examining the expression pattern of a wobbly fly phenotype. you have flies that fly straight and those having a wobble flight. when you cross a straight flying strain with a strain showing a wobble flight, all the f1 flies fly straight. in the f2 generation, you get 762 straight flying flies and 238 wobbly flies. your null hypothesis is that one gene controls flight patterns and that straight is dominant to wobbly. use chi square analysis to test your hypothesis. what is your chi square number? do you reject or fail to reject the null hypothesis?

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

i think it would be c

mark brainliest if im right

step-by-step explanation:

ιт ιѕ 12 αв

нσρє ι ¢συℓ∂ нєℓρ уα

b. is true. hope this . happy