What are the solutions to the equations x^2(4x-3) (5x-1)=0

x can be equal to 0 or 3/4 or 1/5

Step-by-step explanation:

to reach the result to a formula that is equal 0 you need to make at least one of the number 0

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

the graph is negative for all real values of x where   -6 < x < -2.

step-by-step explanation:

this refers to the values of f(x) in the area below the x-axis.