Acoin is to be tossed as many times as necessary to turn up one head. thus the elements c of the sample space c are h, th, tth, ttth, and so forth. let the probability set function p assign to these elements the respective probabilities 1 2 , 1 4 , 1 8 , 1 16 , and so forth. show that p(c) = 1. let c1 = {c : c is h, th, tth, ttth, or h}. compute p(c1). next, suppose that c2 = {c : c is h or h}. compute p(c2), p(c1 ∩ c2), and p(c1 ∪ c2).

Step-by-step explanation:

As stated in the question, the probability to toss a coin and turn up heads in the first try is , in the second is , in the third is and so on. Then, P(C) is given by the next sum:

This is a geometric series with factor . Then is convergent to . With this we have proved that P(C)=1.

Now, observe that

Then

and

n

step-by-step explanation:

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1