Two mechanics, bonita rich, and pamela pearson, take 7 hours to rebuild an engine when they work together. if each worked alone, bonita, the more experienced mechanic, could complete the job 3 hours faster than pamela. how long would it take each of them to rebuild the engine working alone?

Step-by-step explanation:

Let b represent the number of hours it takes Bonita to rebuild an engine. Then b+3 is the number of hours it takes Pamela. When they work together, their total rate of work in "rebuilds per hour" is ...

  1/b + 1/(b+3) = 1/7

Multiplying by the product of the denominators, we have ...

  7(b+3) +7b = b(b+3)

  b² -11b = 21 . . . . . . . . . subtract 14b

  b² -11b +30.25 = 51.25 . . . . complete the square by adding (11/2)^2

  (b -5.5)² = 51.25 . . . . . . . . . . write as a square

  b = 5.5 + √51.25 . . . . . take the square root and add 5.5

  b ≈ 12.65891 . . . . hours

Working alone, Bonita could rebuild an engine in about 12.66 hours; Pamela could do it in about 15.66 hours.

step-by-step explanation:

a child is 12 years old, and his father is 32 years older. in how many years will the age of the father be 2 times the age of the child?

******************

this needs to be the answer format, or else your answer is incomplete.

if the number of years is x, then the equation is

in __ years