As soon as possible
the number of lattes sold daily for two coffee shops is shown in the table:
lattes
12
52
93
33
51
15
46
45
based on the data, what is the difference between the median of the data, including the outlier and excluding the outlier?
a.46
b.45.5
c.45
d.0.5

D

Step-by-step explanation:

First, we need to order the numbers from least to greatest. Let's do this:

12, 15, 33, 45, 46, 51, 52, 93

The median would be the average of 4th and 5th numbers [since there are 8 numbers, the median would be that of 8/2 = 4th and next, 5th number].

So 4th number is 45 and 5th number is 46, average would be (45+46)/2 =  45.5

Median = 45.5

Now, looking at the list the "outlier" would be "93". If we take this away, now we have:

12, 15, 33, 45, 46, 51, 52

Now, there are 7 numbers, and the median is the "middle" number, which is 4th number. This is the median, which is 45.

The difference, thus, is

45.5 - 45 = 0.5

Correct answer is D

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

false

step-by-step explanation: