Acompany can produce a toy bear at a cost of $5 per bear. when the company sells the bears at a price of $34, they can sell 560 bears each week. it is estimated that for every $0.50 decrease in the price, they can sell 20 more bears. find the price that will maximize the profit for the company.

$290

Step-by-step explanation:

Costing price of a toy bear = $5.00

Selling price of a toy bear = $34.00

Profit comes from each toy bear = 34.00 - 5.00

                                                      = $29.00

Company can sell the number of toy bears each week = 560

The profit for the week = 560 × 29.00 = $16,240

If the company decrease $0.50 in the price.

The new price would be = $34.00 - $0.50

                                         = $33.50

The profit from each bear = 33.50 - 5.00 = $28.50

They can sell 20 more bears.

Now the number of sale of bears = 560 + 20

                                                        = 580

Now the profit for the week = 580 × 28.50

                                              = $16,530

The price that will maximize the profit = 16,530 - 16240

                                                                   = $290

∈3,600

step-by-step explanation:

1,407.5 hours

step-by-step explanation:

we first convert all the time to hours and then sum them up.

there are 24 hours in 1 day, in 58 days, there are 24 x 58 = 1,392 hours.

there are 60 minutes in 1 hour, thus, 30 minutes will be equivalent to 30 / 60 = 0.5 hours.

therefore, the number of hours it will take mercury to complete a full rotation is 1,392 + 15 + 0.5 = 1,407.5 hours