Lim x → 4 1 + 1 4 x = 2 given ε > 0, we need δ such that if 0 < |x − 4| < δ, then 1 + 1 4 x − 2 . but 1 + 1 4 x − 2 < ε ⇔ 1 4 x − 1 < ε ⇔ 1 4 |x − 4| < ε ⇔ |x − 4| < . so if we choose δ = then 0 < |x − 4| < δ ⇒ 1 + 1 4 x − 2 < ε. thus, lim x → 4 1 + 1 4 x = 2 by the definition of a limit.

if you are saying purchasing 3 social media ads and one newspaper ad counts as one purchase then there are:

6 purchases

if you are asking how many of each then:

18 social media ads

6 newspaper ads

1. perpendicular

2. parallel

3. perpendicular

3/20

step-by-step explanation:

well, there are 20 outcomes, and 3 of them you want. so, 3/20