The minimum of a parabola is located at (–1, –3). the point (0, 1) is also on the graph. which equation can be solved to determine the a value in the function representing the parabola? 1 = a(0 + 1)2 – 3 1 = a(0 – 1)2 + 3 0 = a(1 + 1)2 – 3 0 = a(1 – 1)2 + 3

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

kjgfcvbjkl

step-by-step explanation:

sdfghjkl; vbnm,

r and t.

both are 64 degrees.