Karissa begins to solve the equation . her work is correct and is shown below. three lines of math. the first line, startfraction one-half endfraction left-parenthesis x minus 14 right-parenthesis plus 11 equals startfraction one-half endfraction x minus left-parenthesis x minus 4 right-parenthesis. the second line, startfraction one-half endfraction x minus 7 plus 11 equals startfraction one-half endfraction x minus x plus 4. the third line startfraction one-half endfraction x plus 4 equals negative startfraction one-half endfraction x plus 4. when she subtracts 4 from both sides, results. what is the value of ?

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).

with btw u said 100pts but it clearly says

i answerd and just got 10pts

no hate

what statement? is there an image?