Find four consecutive integers such that the sum of the two largest subtracted from three times the sum of the two smallest is 70

18, 19, 20, 21

Step-by-step explanation:

Just like any of these problems, we should start by forming an equation for us to get a reference and plug in. We'll be using x as our variables.

As we have four consecutive integers (and not multiples) we can assume that the integers will be x, x+1, x+2, and x+3.

The sum of the two largest integers we have equals: n+2 + n+3 = 2n+5

and three times the sum of the two smallest = 3(n + n+1) = 6n+3

and the sum of t he two largest subtracted from three times the sum of the two smallest = (6n+3) - (2n+5) = 4n-2

4n-2=70

4n=68

n = 18.

n = 18, n+1 = 19, n+2 = 20, n+3 = 21

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation:

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: