Suppose abby tracks her travel time to work for 60 days and determines that her mean travel time, in minutes, is 35.6. assume the travel times are normally distributed with a standard deviation of 10.3 min. determine the travel time such that 17.36% of the 60 days have a travel time that is at least . you may find this standard normal distribution table or this list of software manuals useful. give your answer rounded to two decimal places.

the answer is 45.28 minutes

Step-by-step explanation:

Let X be the travel time in minutes

X is normally distributed with μ= 36.6 and σ=10.3 i.e. X~N (35.6, 10.3)

The travel time x such that 17.36% of the 60 days have a travel time that is at least x is given by,

P(X>x)= 0.1736

P(X<x)= 0.8264

P(Z<x−35.6/10.3)= 0.8264

P(Z<0.940)=0.8264

x−35.6/10.3= 0.940

x=0.940* 10.3+35.6=45.28

Therefore, x is equal to 45.28 minutes

step-by-step explanation:

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is           symmetric about the line y = 120,000.

step-by-step explanation:

given that megan owns a clothing boutique.

the profits of 2010, 11, are recorded and shown as follows:

years since     2010 0     1     2     3       4       5

profits made in 1000's   39       84     111     120   111     84

we find that profit gradually increases form 2010 to 2013 upto 120,   then starts decreasing.

the profits for 2012 and 2014 are the same while that of 2011 and 2015 are also the same.

this shows that there is symmetry about the line profit = 120000

hence answer is:

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is           symmetric about the line y = 120,000.

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it could be 1,3 and more others to create a cylinder.

step-by-step explanation: