The data represent the results for a test for a certain disease. assume one individual from the group is randomly selected. find the probability of getting someone who tests negative, given that he or she did not have the disease. the individual actually had the disease yes no positive 137 7 negative 36 120

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

x = 12

y = 1

for the points!

ѕнє ¢αи ∂яινє 132 кιℓσмєтєяѕ

нσρє ι ¢συк∂ нєℓρ

12 cups   is the answer

step-by-step explanation: