Avector is defined as having magnitude of 15 m and a direction of east. multiply this vector by the scalar value of –6. what is the resultant vector’s magnitude and direction?
what are the components of a vector c→ if its magnitude is 8.9 m/s and it makes an angle of –40° with the +x-axis?

Step-by-step explanation:

1. The magnitude of the multiplier is 6, so the magnitude of the new vector is 6×(15 m) = 90 m. The sign on the multiplier is negative, so the new vector will be in the opposite direction of East. It will be 90 m West.

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2. The components can be found from ...

  (8.9 m/s)(cos(-40°), sin(-40°)) ≈ (6.82, -5.72) m/s

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One or both of the components will usually be irrational if the angle is a rational number of degrees not a multiple of 90°. Here, we have rounded to 2 decimal places.

answer: 2530

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step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

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m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0