Let a > 2 and b be positive integers and suppose a|(b! + 1). prove that a > b. hint: follow these steps: aim for a contradiction. suppose the opposite of what you are asked to suppose that a sb. then aſ why? ? we are also given that al(b! + 1). so by problem 4, a will divide the difference of (b! + 1) and b! what does that tell you?
recall that b! = 1.2. (b-2)(b - 1). the product of all natural numbers from 1 to b.