Yp=+8+10+12++ 106 and q=2+4+6+8+ 104 are sums of arithmetic sequences, determine which is greater, por q, and by how much

P is greater by 94.

Step-by-step explanation:

P =                   8 + 10 + 12 + + 102 + 104 + 106

Q= 2 + 4 + 6 + 8 + 10 + 12 + + 102 + 104

The terms from 8 + 10 + ... + 104 are the same on both P and Q.

Therefore, the different terms are the 106 in P and the 2 + 4 + 6 in Q.

Clearly 106 > 2 + 4 + 6, so P is greater.

To know by how much we would subtract 2 + 4 + 6 = 12 from 106.

106 - 12 = 94.

step-by-step explanation:

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the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!