Prove the identity (a + b)^2 = a ^2 + 2ab + b^2 for all natural numbers a, b.

Step-by-step explanation:

To prove the identity we just manually compute the left hand side of it, simplify it and check that we do get the right hand side of it:

(that's the definition of squaring a number)

(we distribute the product)

(we just use square notation instead for the first and last term)

(since product is commutative, so that ab=ba)

(we just grouped the two terms ab into a single term)

correct answer is infinitely many solutions

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

solving the above equation:

4x + 6 = -4 +4x +10

combining like terms

4x -4x = -4+10-6

0=0

since both sides are 0=0, we end up into true statement it means it has infinite many solutions.

so correct answer is infinitely many solutions

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles