If f(x) = х2 – 2x and g(x) = 6х +4, for which vаluе оf x does (f + g)(x) = 0?

x = - 2

Step-by-step explanation:

(f + g)(x) = f(x) + g(x)

f(x) + g(x) = x² - 2x + 6x + 4 = x² + 4x + 4

Equating to zero, that is

x² + 4x + 4 = 0 ← left side is a perfect square

(x + 2)² = 0, thus

x + 2 = 0 ⇒ x = - 2

Step-by-step explanation:

ƒ(x) = x² - 2x

g(x) = 6x + 4

(f + g)(x) = x² - 2x + 6x + 4 = x² + 4x + 4  

Check:

OK.

step-by-step explanation: it is d