Aprojectile is launched from ground level with an initial velocity of vo feet per second. neglecting air resistance, its height in feet t seconds after launch is given by s= -16t^2+vot find the time that the projectile will (a) reach a height of 128 ft and (b) return to the ground when vo=96 feet per second

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17

answ5

step-by-step explanation:

u have to pay atttion to me

hi there

the slope is 1/3.

this is because from the y-intercept, you go up one, and you go to the right three, to get to the next exact point on the graph. this is known at the “rise over run.”

p.s. (if you need it).your y-intercept is -2, because that is the point on the graph where the line crosses the y-axis.

hope that : )