If y varies directly as x and y is 48 when x is 48 when x is 6 which expression can be used to find the values of y when x is 2

the expression is

y=8x

Step-by-step explanation:

y varies directly as x is written as

introducing constant

y=kx

from the question, when y=48, x=6

substitute it in the formula

48=6k

making k the subject by dividing through by 6

k=8

putting the value of k in the expression,

y=8x

the value of y when x=2

y=8×2

y=16

thus the value of y when x=2 is 16.

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.