Find the value or values of x in the quadratic equation x2=6x-9.

x² = 6x - 9, or x² - 6x + 9 = 0, or x² - 2*x*3 + 3² = 0, or (x-3)² = 0 => x₁ = x₂ = 3.

Green eyes.

Hi Harris

x²=6x-9

First thing we need to do is

subtract 6x-9 from the booth sides

x²-(6x-9)=6x-9-(6x-9)

x²-6x+9=0

Now we gonna factor the left side

(x-3)(x-3)=0

Set factor equal 0

x-3=0 or x-3=0

x=3

I hope that's help !

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval