The line segment ef has a midpoint with coordinates m (-2,2). use the formula to find the coordinates of the other endpoint given that e is located at coordinates (2,8).

The answer to your question is:   F = (-6, -4)

Step-by-step explanation:

Segment = EF

mpM = (-2, 2)

first point = E = (2, 8)

second point = F = (x, y)

Formula

      Xmp = (x1 + x2) / 2                         Ymp = (y1 + y2) / 2

      x2 = 2xmp - x1                                y2 = 2ymp - y1

Process

     x2 = 2(-2) - 2                                   y2 = 2(2) - 8

     x2 = -4 - 2                                       y2 = 4 - 8

     x2 = -6                                            y2 = -4

                     F = (-6, -4)

3, nah jk it's 2

step-by-step explanation:

it is 3 cause i'm sanic

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12