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Mathematics, 11.09.2019 00:30 mcccreamullinsr

The work of a student to solve a set of equations is shown:
equation 1: m = 8 + 2n
equation 2: 4m = 4 + 4n
step 1: βˆ’4(m) = βˆ’4(8 + 2n) [equation 1 is multiplied by βˆ’4.]
4m = 4 + 4n [equation 2]
step 2: βˆ’4m = βˆ’32 βˆ’ 8n [equation 1 in step 1 is simplified.]
4m = 4 + 4n [equation 2]
step 3: βˆ’4m + 4m = βˆ’32 βˆ’ 8n + 4n [equations in step 2 are added.]
step 4: 0 = βˆ’32 βˆ’ 4n
step 5: n = βˆ’8
in which step did the student first make an error?
a.) step 1
b.) step 2
c.) step 3
d.) step 4

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Answers: 1

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The work of a student to solve a set of equations is shown:
equation 1: m = 8 + 2n
equ...
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