Aproblem states: "there are 2 more horses than cows in a field. there are 16 animals in the field in all. how many horses are there in the field? "
let h represent the number of horses.
which equation represents the situation?
2h + 2 = 16
2(h+2)=16
h + 2 = 16
2h−2=16

2h-2=16

Step-by-step explanation:

Let

h > the number of horses

c > the number of a cows

we know that

h+c=16 > equation A

h=c+2

c=(h-2) > equation B

Substitute equation B in equation A and solve for h

h+(h-2)=16

2h-2=16

2h=16+2

2h=18

h=9

therefore

The equation that represent the situation is

2h-2=16

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).