World problem
in.
you are told that in a billiards shot, the cue ball was
shot at the eight ball, which was 8 inches away. as a
result, the eight ball rolled into a pocket, which was 6
inches away.
knowing that the angle made with the path of the cue
ball and the resulting path of the eight ball is larger
than 90°, it can be determined that the original distance
from the cue ball to the pocket was greater than
inches.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

96 39 cause 135 -96=39 im smart (i used a calculater)