Show that the points a (-3, 2), b (-6, 4) and c (1, 8) are vertices of a right triangle.

See below.

Step-by-step explanation:

For the triangle to be a right triangle there must be a pair adjacent sides which are at right angles to each other - that is whose slope product = -1.

Slope of AB = (4-2)/(-6- -3) = -2/3.

Slope of BC = (8-4)/ (1 - - 6) =  2/7

Slope of AC =  (8-2) / (1 - -3) = 6/4 = 3/2.

Now 3/2 * -2/3 = -1 so sides AB and AC are at right angles and the 3 points are the vertices of a right triangle.

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°