The two-way table shows the ages of the players on different soccer teams. a 6-column table has 4 rows. the first column has entries 8 years old, 9 years old, 10 years old, total. the second column is labeled team a with entries 4, 9, 2, 15. the third column is labeled team b with entries 6, 4, 3, 13. the fourth column is labeled team c with entries 8, 3, 5, 16. the fifth column is labeled team d with entries 3, 7, 4, 14. the sixth column is labeled total with entries 21, 23, 14, 58. which statement is true? the probability that a randomly selected player on team a is 8 years old is startfraction 4 over 21 endfraction. the probability that a randomly selected 8-year-old player is on team c is startfraction 16 over 21 endfraction. the probability that a randomly selected player on team c is 10 years old is startfraction 5 over 16 endfraction. the probability that a randomly selected 10-year-old player is on team b is startfraction 13 over 58 endfraction.

The true statement is:  The probability that a randomly selected player on Team C is 10 years old is .

Step-by-step explanation:

According to the table the total number of 10 years old players on Team C is 5 and the total number of all ages players (8, 9 and 10 years old) on Team C is 16, so the probability that a randomly selected player on Team C is 10 years old is 5/16.

it is c; The probability that a randomly selected player on Team C is 10 years old is Fraction 5 Over 16

Step-by-step explanation:

because edge said that it is correct

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions